Asked by Rosagne
solve sin theta = 1/2,90 degrees less than theta less than 180 degrees
Answers
Answered by
Reiny
make sure your calculator is set to degrees
2nd
sin
(1/2.9)
= 20.17
You want the angle between 0 and 180, that is in the I or II quadrant.
20.17° is in quadrant I
the angle in quadrant II would be 180 - 20.17 = 159.83°
check:
take the sine of each of those angles and compare it to 1/2.9
2nd
sin
(1/2.9)
= 20.17
You want the angle between 0 and 180, that is in the I or II quadrant.
20.17° is in quadrant I
the angle in quadrant II would be 180 - 20.17 = 159.83°
check:
take the sine of each of those angles and compare it to 1/2.9
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.