Question
A stone is launched straight up by a slingshot. Its initial speed is 18.8 m/s and the stone is 1.30 m above the ground when launched.
How much time elapses before the stone hits the ground
How much time elapses before the stone hits the ground
Answers
drwls
Solve this equation for time t.
Y = 1.3 + 18.8 t - (g/2) t^2 = 0
(Assume g = 9.8 m/s^2, the value on Earth)
Y = 1.3 + 18.8 t - (g/2) t^2 = 0
(Assume g = 9.8 m/s^2, the value on Earth)