Question
A stone is launched straight up by a slingshot. Its initial speed is 20.6 m/s and the stone is 1.59 m above the ground when launched. How high above the ground does the stone rise? How much time elapses before the stone hits the ground?
Answers
bobpursley
hf=hi+vi*t-4.9t^2
hf=0, hi=1.59, vi given, solve for time t in the air.
how high? at the top, vf=0
vf^2=vi^2-2g*height
solve for height.
hf=0, hi=1.59, vi given, solve for time t in the air.
how high? at the top, vf=0
vf^2=vi^2-2g*height
solve for height.