Nope. That's way too fast.
How long does it take to fall to a height of -250m?
35t - 4.9t^2 = -250
t = 11.56
Now,
v = 35 - 9.8t = -78.26
A ball is launched straight up from the edge of a cliff that is 250 m high. The ball's motion is given by s = 35t - 4.9t^2 where s is the ball's height in meters above the cliff top at time t seconds.
With what velocity does the ball strike the ground at the base of the cliff?
Answer: -285 m/sec
Is that correct?
1 answer
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