Asked by anonymous
A rocket is launched straight up with a constant acceleration. Three seconds after lift off, a small part of the rocket falls off the side. The small part hits the ground 7 seconds later. Ignoring air resistance, what was the acceleration of the rocket?
Answers
Answered by
drwls
Initial velocity of fragment, at release
Vo = 3 a
Height where fragment is released:
H = (a/2)t^2 = (9/2)a
Since Time to reach ground = 7s:
y(t=7) = H +Vo*7 -(g/2)*49 = 0
(9/2)a + 21a -24.5g = 0
a = (24.5/25.5) g = 9.4 m/s^2
Vo = 3 a
Height where fragment is released:
H = (a/2)t^2 = (9/2)a
Since Time to reach ground = 7s:
y(t=7) = H +Vo*7 -(g/2)*49 = 0
(9/2)a + 21a -24.5g = 0
a = (24.5/25.5) g = 9.4 m/s^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.