Asked by Rebekah L.
A toy rocket is launched into the air at an initial velocity of 32 ft/sec, as shown on the graph below. The function s(t)=-16t^2+32t+128 gives the height of the rocket (in feet) at time t (seconds). When does the rocket hit the ground? Show your work.
Answers
Answered by
R_scott
the ground is zero feet
0 = -16t^2 + 32t + 128
dividing by -16 ... 0 = t^2 - 2t - 8
factoring ... 0 = (t - 4) (t + 2)
0 = t - 4 ... t = 4
0 = -16t^2 + 32t + 128
dividing by -16 ... 0 = t^2 - 2t - 8
factoring ... 0 = (t - 4) (t + 2)
0 = t - 4 ... t = 4
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.