Asked by Jeff
A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 6.10s later. What was the rocket's acceleration?
Answers
Answered by
bobpursley
consider the bolt when on the rocket.
Vfbolt=a*4
hfbolt=1/2*a*16=8a
Now in the free fall portion, these become vi, and hi for the bolt
vfbolt=vibolt-g*6.1=4a-6.1g
hfbolt=6.1*4a-1/2 g 6.1^2+8a=0
from this second equation
you can solve for a.
Vfbolt=a*4
hfbolt=1/2*a*16=8a
Now in the free fall portion, these become vi, and hi for the bolt
vfbolt=vibolt-g*6.1=4a-6.1g
hfbolt=6.1*4a-1/2 g 6.1^2+8a=0
from this second equation
you can solve for a.
Answered by
idk
5.627 m/s^2
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