A ball is thrown from a cliff upward with a speed of 20 m/s, the angle is 33 degrees and the ball hits the ground 9.2 seconds later, how high is the cliff to the nearest meter?

Answer 1

Is the 33 degrees with respect to vertical or horizontal? You need the initial vertical velocity component to answer the question. Call it Vyo.

Vyo*t - (g/2) t^2 = -H

Solve for the cliff height H. You know what t is: 9.2 s.