Question
A ball is thrown from a cliff of 10m with an initial velocity of 2.00m/s. What is the velocity of the ball just before it hits the ground?
Answers
bobpursley
finalKE=initialPE+initialKE
1/2 m v^2=mg*10+1/2 m*2^2
v=sqrt(2*9.8*10+4) check the math.
1/2 m v^2=mg*10+1/2 m*2^2
v=sqrt(2*9.8*10+4) check the math.