Asked by Anonymous

A ball is thrown from a cliff of 10m with an initial velocity of 2.00m/s. What is the velocity of the ball just before it hits the ground?

Answers

Answered by bobpursley
finalKE=initialPE+initialKE
1/2 m v^2=mg*10+1/2 m*2^2
v=sqrt(2*9.8*10+4) check the math.
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