Asked by Anonymous
A ball is thrown from a cliff of 10m with an initial velocity of 2.00m/s. What is the velocity of the ball just before it hits the ground?
Answers
Answered by
bobpursley
finalKE=initialPE+initialKE
1/2 m v^2=mg*10+1/2 m*2^2
v=sqrt(2*9.8*10+4) check the math.
1/2 m v^2=mg*10+1/2 m*2^2
v=sqrt(2*9.8*10+4) check the math.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.