Asked by LISA
                the sum of the squares pf two postive consecutive even integers is 41. Find the integers.
            
            
        Answers
                    Answered by
            Ms. Sue
            
    Is it?
3 and 4
4 and 5
5 and 6
    
3 and 4
4 and 5
5 and 6
                    Answered by
            LISA
            
    its 4 and 5
    
                    Answered by
            Ms. Sue
            
    Right.
    
                    Answered by
            Reiny
            
    the number are even
so let the first be x
then the second is x+2
x^2 + (x+2)^2 = 41
x^2 + x^2 + 4x + 4 = 41
2x^2 + 4x - 37 = 0
No integer solution
We could tell from the beginning that this problem has no solution
the square of any even integer is even
the sum of two even number is even, but 41 is odd, so NO WAY!
    
so let the first be x
then the second is x+2
x^2 + (x+2)^2 = 41
x^2 + x^2 + 4x + 4 = 41
2x^2 + 4x - 37 = 0
No integer solution
We could tell from the beginning that this problem has no solution
the square of any even integer is even
the sum of two even number is even, but 41 is odd, so NO WAY!
                    Answered by
            Ms. Sue
            
    I misread the problem.
    
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