Asked by LISA
the sum of the squares pf two postive consecutive even integers is 41. Find the integers.
Answers
Answered by
Ms. Sue
Is it?
3 and 4
4 and 5
5 and 6
3 and 4
4 and 5
5 and 6
Answered by
LISA
its 4 and 5
Answered by
Ms. Sue
Right.
Answered by
Reiny
the number are even
so let the first be x
then the second is x+2
x^2 + (x+2)^2 = 41
x^2 + x^2 + 4x + 4 = 41
2x^2 + 4x - 37 = 0
No integer solution
We could tell from the beginning that this problem has no solution
the square of any even integer is even
the sum of two even number is even, but 41 is odd, so NO WAY!
so let the first be x
then the second is x+2
x^2 + (x+2)^2 = 41
x^2 + x^2 + 4x + 4 = 41
2x^2 + 4x - 37 = 0
No integer solution
We could tell from the beginning that this problem has no solution
the square of any even integer is even
the sum of two even number is even, but 41 is odd, so NO WAY!
Answered by
Ms. Sue
I misread the problem.
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