Question

The sum of the squares of three consecutive integers is 194. what are the integers?

Answer 1

Fist number= a
Second number= a+1
Third number= a+2

a^2+(a+1)^2+(a+2)^2=194

(a+1)^2=a^2+2*a*1+1^2=a^2+2a+1

(a+2)^2=a^2*2a*2+2^2=a^2+4a+4

a^2+a^2+2a+1+a^2+4a+4=194

3a^2+6a+1+4=194

3a^2+6a+5-194=0

3a^2+6a-189=0

The exactsolutions of this equation are:

a=7 and a=-9

Solution:
First number 7
Second number 7+1=8
Third number 7+2=9

7^2+8^2+9^2=49+64+81=194

Answer 2

how did u get a to b 7 and 9

Answer 3

In google type:
"quadratic equation online"

When you see list of result click on:

webgraphingcom/quadraticequation_quadraticformula.jsp

When this page be open in rectacangle type equation:

3a^2+6a-189=0

and click option solve it!

You will see solutions of this equation Step-by-step