Question

The sum of the squares of three consecutive positive integers is 365
What are these integers?
Please write this problem in quadratic equation form please

Answer 1

let x = smallest integer, then the other integers are x+1 and x +2.

x^2 + (x+1)^2 + (x+2)^2 = 365

Square terms and combine.

Answer 2

X^2+(x+1^2)+(x+2^2)=365 3x^2+6x-360=0 x^2+2x-120=0 (x+12)(x-10)=0 x=10 or -12 Answer=10,11,12 or -12,-11,-10