The sum of the squares of three consecutive positive integers is 365

Question

The sum of the squares of three consecutive positive integers is 365 
What are these integers?
Please write this problem in quadratic equation form please

PsyDAG · Accepted Answer

let x = smallest integer, then the other integers are x+1 and x +2. x^2 + (x+1)^2 + (x+2)^2 = 365 Square terms and combine.

Vin mwale · Answer

X^2+(x+1^2)+(x+2^2)=365 3x^2+6x-360=0 x^2+2x-120=0 (x+12)(x-10)=0 x=10 or -12 Answer=10,11,12 or -12,-11,-10