An object moves along a parabolic path defined by the equation y = 2x 2 + 1 in such a way that the y-value is decreasing at a constant rate of 2 units per second. At what rate is the x-coordinate changing when x = 3/2?

Answer 1

I will assume you meant to type
y = 2x^2 + 1
dy/dt = 4x dx/dt

given dy/dt = -2 when x = 3/2

-2 = 4(3/2) dx/dt
-2 = 6 dx/dt
dx/dt = -2/6 = -1/3

Answer 2

post it.