If you make a solution by dissolving 25.0g of sodium chloride in 100.0 mL of water. What is the boiling point of the solution?

Answer 1

n=m divided by mr
n=25 divided by mr of nacl 23+35.5
n=c*v

Answer 2

moles NaCl = grams/molar mass
Solve for moles.

molality = moles/kg solvent
Solve for molality

delta T = Kb*m
Solve for delta T. Then add to the normal boiling point.