Question
If you make a solution by dissolving 25.0g of sodium chloride in 100.0 mL of water. What is the boiling point of the solution?
Answers
n=m divided by mr
n=25 divided by mr of nacl 23+35.5
n=c*v
n=25 divided by mr of nacl 23+35.5
n=c*v
moles NaCl = grams/molar mass
Solve for moles.
molality = moles/kg solvent
Solve for molality
delta T = Kb*m
Solve for delta T. Then add to the normal boiling point.
Solve for moles.
molality = moles/kg solvent
Solve for molality
delta T = Kb*m
Solve for delta T. Then add to the normal boiling point.
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