Asked by Natalya
A solution is prepared by dissolving 104.1 grams of barium chloride, BaCl2 in 1000. grams of water? What is the boiling point of this solution? [The boiling point elevation constant for water is 0.52°C/mole solute in 1000g of water]
Answers
Answered by
DrBob222
mols BaCl2 = grams/molar mass = ?
molality = m = mols/kg solvent
delta T = i*Kb*m
i = 3 for BaCl2
Solve for delta T and add to the normal boiling point of water for the final b.p.
molality = m = mols/kg solvent
delta T = i*Kb*m
i = 3 for BaCl2
Solve for delta T and add to the normal boiling point of water for the final b.p.
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