Question
A baseball is thrown at an angle of 26 degrees relative to the ground at a speed of 22.1 m/s. The ball is caught 39.2327 m from the thrower.
The acceleration due to gravity is 9.81 m/s2 .
How high is the tallest spot in the ball’s path? Answer in units of m
The acceleration due to gravity is 9.81 m/s2 .
How high is the tallest spot in the ball’s path? Answer in units of m
Answers
Vo = 22.1m/s @ 26deg.
Yo = ver. = 22.1sin26 = 9.69m/s.
hmax = (Yf^2 - Yo^2) / 2g,
hmax = (0 - (9.69)^2) / -19.6 = 4.79m.
Yo = ver. = 22.1sin26 = 9.69m/s.
hmax = (Yf^2 - Yo^2) / 2g,
hmax = (0 - (9.69)^2) / -19.6 = 4.79m.
Related Questions
a baseball is thrown at an angle of 25 degrees relative to the ground at a speed of 23.0 m/s. if the...
A baseball is thrown at an angle of 25 degrees relative to the ground at a speed of 23.0 m/s. If the...
a baseball is thrown at an angle of 24 degrees relative to the ground at a speed of 23.4m/s. the bal...
A baseball is thrown at an angle of 20º relative to the ground at a speed of 25.0 m/s. If the ball w...