Horizontal velocity component = 22.3 cos23 = 20.53 m/s
Initial horizontal velocity component
Vyo = 22.3 sin23 = 8.71 m/s
Time ball is in the air = 36.4649/20.53 = 1.78 s.
I did not have to use the horizontal velocity component to get that result; one can use Voy to get the time in the air as follows:
T = 2*Vyo/g = 1.78 s
Both methods agree, as they should.
A baseball is thrown at an angle of 23◦ relative to the ground at a speed of 22.3 m/s. The ball is caught 36.4649 m from the thrower. The acceleration due to gravity is 9.81 m/s2 . How long is it in the air?
How high is the tallest spot in the ball’s path?
2 answers
a person standing at the edge of a seaside cliff kick is 51 m above the water's surface, as shown. the acceleration of gravity is 9.81 m/s^2
a) how long does it take for the stone to fall to the water?
b) with what speed does the stone strike the water.
a) how long does it take for the stone to fall to the water?
b) with what speed does the stone strike the water.