Question
A stone is thrown up at an angle of 30degrees to the horizontal with a speed of 20metres per second from the edge of a cliff 15m above sea level, so that the stone lands in the sea. Find how long the stone is in the air and how far from the base of the cliff it lands.
Answers
Vo = 20m/s[30o].
Xo = 20*Cos30 = 17.3 m/s.
Yo = 20*sin30 = 10 m/s.
Yf = Yo + g*Tr.
Yf = 0.
g = -9.8 m/s^2.
Tr = Rise time = ?.
h = 15 + Yo*Tr + 0.5g*Tr^2 = Meters above sea level.
g = -9.8 m/s^2.
h = 0.5g*Tf^2.
g = 9.8 m/s^2.
Tf = Fall time = ?.
Tr + Tf = Time in air.
Dx = Xo*(Tr+Tf) = Hor. distance from base.
Xo = 20*Cos30 = 17.3 m/s.
Yo = 20*sin30 = 10 m/s.
Yf = Yo + g*Tr.
Yf = 0.
g = -9.8 m/s^2.
Tr = Rise time = ?.
h = 15 + Yo*Tr + 0.5g*Tr^2 = Meters above sea level.
g = -9.8 m/s^2.
h = 0.5g*Tf^2.
g = 9.8 m/s^2.
Tf = Fall time = ?.
Tr + Tf = Time in air.
Dx = Xo*(Tr+Tf) = Hor. distance from base.
Related Questions
Suppose a stone is thrown at an angle of 30 degrees below the horizontal, if it strikes the ground 5...
A stone is thrown from the top of a cliff with speed v at an angle above the horizontal. Air resista...
A stone is thrown from the top of a cliff with speed v at an angle above the horizontal. Air resista...