Asked by Anonymous
A baseball is thrown at an angle of 20◦ relative to the ground at a speed of 25.8 m/s. The ball is caught 43.6152 m from the thrower.
The acceleration due to gravity is
9.81 m/s2 .
The acceleration due to gravity is
9.81 m/s2 .
Answers
Answered by
Damon
vertical problem
Vi = 25.8 sin 20 = 8.824 m/s
v = Vi - 9.81 t
at top v = 0
t = 8.824/9.81 = .900 seconds at top
(therefore 1.8 seconds in air by the way)
h = Vi t - (9.81/2) t^2
= 8.824(.9) - 4.9(.81)
= 7.94 - 3.97 = 3.97 meters high
horizontal problem
u = 25.8 cos 20 = 24.2
times time in air of 1.8 s
= 43.6 meters sure enough
Vi = 25.8 sin 20 = 8.824 m/s
v = Vi - 9.81 t
at top v = 0
t = 8.824/9.81 = .900 seconds at top
(therefore 1.8 seconds in air by the way)
h = Vi t - (9.81/2) t^2
= 8.824(.9) - 4.9(.81)
= 7.94 - 3.97 = 3.97 meters high
horizontal problem
u = 25.8 cos 20 = 24.2
times time in air of 1.8 s
= 43.6 meters sure enough
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.