Question

A baseball is thrown at an angle of 20◦ relative to the ground at a speed of 25.8 m/s. The ball is caught 43.6152 m from the thrower.
The acceleration due to gravity is
9.81 m/s2 .

Answer 1

vertical problem
Vi = 25.8 sin 20 = 8.824 m/s
v = Vi - 9.81 t
at top v = 0
t = 8.824/9.81 = .900 seconds at top
(therefore 1.8 seconds in air by the way)
h = Vi t - (9.81/2) t^2
= 8.824(.9) - 4.9(.81)
= 7.94 - 3.97 = 3.97 meters high

horizontal problem
u = 25.8 cos 20 = 24.2
times time in air of 1.8 s
= 43.6 meters sure enough