Asked by Yousef
Find the first derivative for the following functions
1) f(x) = sin(cos^2x) cos(sin^3x)
2) f(x) = ( tan 2x - tan x ) / ( 1 + tan x tan 2x )
3) f(x) = sin { tan ( sqrt x^3 + 6 ) }
4) f(x) = {sec^2(100x) - tan^2(100x)} / x
1) f(x) = sin(cos^2x) cos(sin^3x)
2) f(x) = ( tan 2x - tan x ) / ( 1 + tan x tan 2x )
3) f(x) = sin { tan ( sqrt x^3 + 6 ) }
4) f(x) = {sec^2(100x) - tan^2(100x)} / x
Answers
Answered by
Steve
Just gonna dump some problems on us?
The solution to your previous posting should help some.
Hints:
1) use product rule, chain rule
2) use quotient rule, chain rule
3) use chain rule, chain rule, chain rule
4) use quotient rule, chain rule
The solution to your previous posting should help some.
Hints:
1) use product rule, chain rule
2) use quotient rule, chain rule
3) use chain rule, chain rule, chain rule
4) use quotient rule, chain rule
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