Question

A manufacture of television sets has a historical defective rate of ten percent.

a. what is the probability that in an hourly production run of 10 televisions, one will be defective

b. What is the probability that in an hourly daily production run of 10 televisions, mo more than two will be defective

Answer 1

Pr(1 defective)=1/10*(9/10)^9*10!/(1!9!)

= .1(.387)10=.387

Pr(more than two)=1-Pr(two)-Pr(one)-Pr(zero)

= 1-.1^2*.9^8 * 10!/(2!8!)-.387-.9^10
= 1-.193-.397-.349=.061

check all this.