Asked by Sarah
Calculate [H3O] an [OH] for a sodium hydroxide solution having a pH of 12.5.
I know this is a strong base, and i got the pH 12.5. But i don't know how to go from there.
I know this is a strong base, and i got the pH 12.5. But i don't know how to go from there.
Answers
Answered by
DrBob222
pH = -log(H^+)
12.5 = 0log.....
-12.5 = log(H^+).
Take antilog both sides to arrive at (H^+). Then
(H^+)(OH^-) = Kw = 1E-14.
You know (H^+), solve for (OH^-).
12.5 = 0log.....
-12.5 = log(H^+).
Take antilog both sides to arrive at (H^+). Then
(H^+)(OH^-) = Kw = 1E-14.
You know (H^+), solve for (OH^-).
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.