Question

what volume of 0.955 M HCl, in milliliters, is required to titrate 2.152g of Na2CO3 to the equivalent point?
Na2CO3(aq) + 2HCl(aq)
2NaCl(aq) + CO2(g) + H2O(1)

can this please be explained in simple step by steps? i am sick and i am having trouble understanding anything.

Answer 1

1. moles Na2CO3 = M x L = ?
2. Convert moles Na2CO3 to moles HCl using the coefficients in the balanced equation. You should get ?moles Na2CO3 x (2 moles HCl/1 mole Na2CO3) = ?moles HCl.
3. M HCl = moles HCl/L HCl. You know moles HCl an M HCl, solve for L HCl and convert to mL.

Answer 2

42.5 mL