Asked by Bushra
Volume of 12M HCL taken for preparing 1M HCL (100 ml Sol {
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Answered by
Anonymous
Let M1=12M and M2= 1M then Let V1=1oo ml and V2=? .: by using the formula M1V1=M2V2 we get V2=M1V1/M2 therefore. V2=12*100/ 1 then V2=1200ml
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