Asked by elizabeth
find limit as x aproches 0 in the equation (5sin(x))/(x^2-13x)
Answers
Answered by
Steve
since the limit = 0/0, lim f/g = lim f'/g'
so, here we have the limit = 5cosx/(2x-13)
as x->0, limit = 5/-13
so, here we have the limit = 5cosx/(2x-13)
as x->0, limit = 5/-13
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