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Find the limit. lim t-->∞ [(t^2 -t)/(t-1)I +√((t+8))j + sin(πt)/ln(t)k]

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Answered by oobleck
huh.
clearly, (t^2-t)/(t-1) = t and goes to ∞
likewise, √(t+8) -> ∞
since ln(t) -> ∞ and |sin(πt)| <= 1, the quotient -> 0
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