Asked by Anonymous
evaluate lim x aproches -1
x^2+6x+5/x^2-3x-4
x^2+6x+5/x^2-3x-4
Answers
Answered by
Jai
lim (x^2 + 6x + 5)/(x^2 - 3x - 4) as x-> -1
Not that we can factor both numerator & denominator,
lim (x+5)(x+1) / (x-4)(x+1)
We can thus cancel the x+1, leaving
lim (x + 5)/(x - 4) as x-> -1
Substituting x = -1,
= (-1 + 5) / (-1 - 4)
= 4 / -5
= -4/5
Hope this helps~ :3
Not that we can factor both numerator & denominator,
lim (x+5)(x+1) / (x-4)(x+1)
We can thus cancel the x+1, leaving
lim (x + 5)/(x - 4) as x-> -1
Substituting x = -1,
= (-1 + 5) / (-1 - 4)
= 4 / -5
= -4/5
Hope this helps~ :3
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