u= sqrt(1-x^4)
du= 1/2sqrt(1-x^4)*(-4x^3)dx
= -2x^3/sqrt(1-x^4) dx
so the integral is
INT -1/u du
Evaluate ∫(2x^3/√(1-x^4))dx
I can't figure out what u and du is...
please help thanks
3 answers
or,
u = 1-x^4
du = -4x^3 du
so
∫(2x^3/√(1-x^4))dx
= -1/2 ∫1/√u du
= (-1/2)(2√u)
= -√(1-x^4)
Extra credit: Can you find the error in bobpursley's solution?
u = 1-x^4
du = -4x^3 du
so
∫(2x^3/√(1-x^4))dx
= -1/2 ∫1/√u du
= (-1/2)(2√u)
= -√(1-x^4)
Extra credit: Can you find the error in bobpursley's solution?
no, but thanks for your answer!
2 answers