Asked by Ishu
Evaluate: 2 log 3 + 3 log 4 + 4 log 5 - 2 log b
Answers
Answered by
oobleck
2 log 3 + 3 log 4 + 4 log 5 - 2 log b
= log 3^2 + log 4^3 + log 5^4 - log b^2
= log (9*64*625/b^2)
= log (360000/b^2)
unless b is a typo for 6, in which case you have log 10000
= log 3^2 + log 4^3 + log 5^4 - log b^2
= log (9*64*625/b^2)
= log (360000/b^2)
unless b is a typo for 6, in which case you have log 10000
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