Asked by Claire
A particle is moving with SHM of period 16s and amplitude 10m. Find the speed of the particle when it is 6.0m from its equilibrium position.
First I found the value of w:
w= 2 pi/ T
= 2 pie/ 16
=0.393 s^-1
Then I used:
v= +/- w root a^2 - x^2
= +/- 0.393 root 10^2 - 6^2
= 3.14 m/s
My problem is in the next question:
How far is the particle in question 1 from its equilibrium position 1.5s after passing through it? What is its speed at this time?
The answers should be 5.6m , 3.3m/s
Can someone help me please? Thanks!
First I found the value of w:
w= 2 pi/ T
= 2 pie/ 16
=0.393 s^-1
Then I used:
v= +/- w root a^2 - x^2
= +/- 0.393 root 10^2 - 6^2
= 3.14 m/s
My problem is in the next question:
How far is the particle in question 1 from its equilibrium position 1.5s after passing through it? What is its speed at this time?
The answers should be 5.6m , 3.3m/s
Can someone help me please? Thanks!
Answers
Answered by
drwls
You can represent displacement vs time as
X = 10 sin (0.393 t), where
t = 0 corresponds to an equilibrium position. The velocity will be
V = 3.93 cos (0.393t)
Substitute t = 1.5 s and you should get the right answers, after rounding off to two significant figures
X = 10 sin (0.393 t), where
t = 0 corresponds to an equilibrium position. The velocity will be
V = 3.93 cos (0.393t)
Substitute t = 1.5 s and you should get the right answers, after rounding off to two significant figures
Answered by
Lily
woah. Will i have to learn this when i grow older?
Answered by
Ms. Sue
Only if you choose to take physics in high school and/or college.
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