Asked by Hope
A 1.6 kg particle moving along the x-axis experiences the force shown in the figure. The particle's velocity is 4.2 m/s at x = 0 m.
The figure or graph has F (N) along the y axis and velocity along the x axis. A diagonal line drops from positive 10 force to -10 force from 0 cm to 4 cm. and crosses the x axis at 2 cm.
What is its velocity at 2 cm and 4 cm?
What formula do I need to use?
The figure or graph has F (N) along the y axis and velocity along the x axis. A diagonal line drops from positive 10 force to -10 force from 0 cm to 4 cm. and crosses the x axis at 2 cm.
What is its velocity at 2 cm and 4 cm?
What formula do I need to use?
Answers
Answered by
drwls
Integrate F dx from 0 to 0.02 m to get the change in kinetic energy (KE) at 2 cm. Use the new value of the KE to get the new velocity. Then do it again for 0.02 to 0.04 m. The KE will decrease, since the force on the particle is in the opposite direction to motion over that interval.
Answered by
Hope
Please explain to me how to integrate-I am unsure exactly what this means in this problem
Thanks
Thanks
Answered by
Peace
Find the area under the line within each interval
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