Asked by David
A particle is moving at 0.75c relative to a lab on Earth. By what percentage is the Newtonian expression for its momentum
in error, i.e., how wrong is the classical formula? (The percentage error is the difference between the erroneous and correct
values, divided by the correct one).
in error, i.e., how wrong is the classical formula? (The percentage error is the difference between the erroneous and correct
values, divided by the correct one).
Answers
Answered by
Damon
p Newton = m v
p relativistic = m v /sqrt(1 = .75^2)
so
100(p relativistic - p newton)/p rel
here 1/sqrt(1-.75^2) = 1.512
so
100 ( 1.512 - 1)/1.512 = 33.9 %
p relativistic = m v /sqrt(1 = .75^2)
so
100(p relativistic - p newton)/p rel
here 1/sqrt(1-.75^2) = 1.512
so
100 ( 1.512 - 1)/1.512 = 33.9 %
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