Asked by Anonymous
A 4.0-kg particle is moving horizontally with a speed of 5.0 m/s when it strikes a vertical wall. The particle rebounds with a speed of 3.0 m/s. What is the magnitude of the impulse delivered to the particle?
Answers
Answered by
Damon
I will help with this, then you do the rest.
impulse = change in momentum = force * time
initial momentum = 4*5 = 20
final momentum = 4*-3 = -12
change = -12 - 20 = -32
magnitude of change of momentum = impulse = 32
impulse = change in momentum = force * time
initial momentum = 4*5 = 20
final momentum = 4*-3 = -12
change = -12 - 20 = -32
magnitude of change of momentum = impulse = 32
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.