Question
a particle moving in the xy plane has velocity components dx/dt =2t and dy/dt = 4. If the particle starts from the origin at t = 0,magnitude of its displacement at t=2 is
Answers
dx/dt=2t, integrate, x=t^2+Cx
dy/dt=4, integrate, y=4t+Cy
We know x(0)=y(0)=0 => Cx=Cy=0
The trajectory of the particle is therefore
<t^2, 4t>
Guess you can find displacement at t=2 with the above information.
dy/dt=4, integrate, y=4t+Cy
We know x(0)=y(0)=0 => Cx=Cy=0
The trajectory of the particle is therefore
<t^2, 4t>
Guess you can find displacement at t=2 with the above information.
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