Asked by James
A particle is moving with the given data. Find the position of the particle.
v(t) = 1.5sqrt(t), s(9) = 33
v(t) = 1.5sqrt(t), s(9) = 33
Answers
Answered by
Steve
v(t) = 3/2 t^(1/2)
s(t) = t^(3/2) + c
33 = 9^(3/2)+c, so c=6
s(t) = t^(3/2) + 6
s(t) = t^(3/2) + c
33 = 9^(3/2)+c, so c=6
s(t) = t^(3/2) + 6
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