Asked by Me

A 2.0 m diameter merry-go-round is initially turning with a 4.2 s period. It slows and stops in 22.0 seconds. Before slowing, what is the speed (in m/s) of a child on the rim?

How many revolutions does the merry-go-round make as it stops?

Answers

Answered by bobpursley
one rev in 4.2 seconds
v= 2PI*radius/4.2

figure that out

Now, average angular velocity= Vi/(2*r)

revolutions= avgangularveloicty*22sec
Answered by yo
This is wrong
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