Asked by A
A playground merry-go-round has a radius of R= 2 m and has a moment of inertia Icm= 9×103kg⋅m2 about a vertical axis passing through the center of mass. There is negligible friction about this axis. Two children each of mass m= 30kg are standing on opposite sides at a distance ro= 1.4m from the central axis. The merry-go-round is initially at rest. A person on the ground applies a constant tangential force of F= 2.5×102N at the rim of the merry-go-round for a time Δt= 12s . For your calculations, assume the children to be point masses.
(a) What is the angular acceleration α of the merry-go-round? (in rad/s2)
α=
(b) What is the angular velocity ωfinal of the merry-go-round when the person stopped applying the force? (in rad/s)
ωfinal=
(c) What average power Pavg does the person put out while pushing the merry-go-round? (in Watts)
Pavg=
(d) What is the rotational kinetic energy R.K.Efinal of the merry-go-round when the person stopped applying the force? (in kg⋅m2/s2)
R.K.Efinal=
(a) What is the angular acceleration α of the merry-go-round? (in rad/s2)
α=
(b) What is the angular velocity ωfinal of the merry-go-round when the person stopped applying the force? (in rad/s)
ωfinal=
(c) What average power Pavg does the person put out while pushing the merry-go-round? (in Watts)
Pavg=
(d) What is the rotational kinetic energy R.K.Efinal of the merry-go-round when the person stopped applying the force? (in kg⋅m2/s2)
R.K.Efinal=
Answers
Answered by
KS
R=2 m, Ic=9000 kg•m², r₀=1.2 m, m=20 kg, F=200 N, Δt=18 s.
I=Ic+2I₀=Ic+2m r₀² =
=9000+2•20•1.2²=9057.6 kg•m².
M=Iα
α=M/I=FR/I =200•2/9057.6 = 0.044 rad/s²
ω=α•Δt =0.044•18=0.792=0.8 rad/s
P=Fv=P ωR = 200•0.8•2 = 320 W.
KE=Iω²/2 = 9057.6•0.8²/2 = 2898.4 J.
I=Ic+2I₀=Ic+2m r₀² =
=9000+2•20•1.2²=9057.6 kg•m².
M=Iα
α=M/I=FR/I =200•2/9057.6 = 0.044 rad/s²
ω=α•Δt =0.044•18=0.792=0.8 rad/s
P=Fv=P ωR = 200•0.8•2 = 320 W.
KE=Iω²/2 = 9057.6•0.8²/2 = 2898.4 J.
Answered by
Shashanoid
please tell the answers for this one --
----------------------------------
A playground merry-go-round has a radius of R= 4 m and has a moment of inertia Icm= 9×103kg⋅m2 about a vertical axis passing through the center of mass. There is negligible friction about this axis. Two children each of mass m= 25kg are standing on opposite sides at a distance ro= 3.2m from the central axis. The merry-go-round is initially at rest. A person on the ground applies a constant tangential force of F= 2.0×102N at the rim of the merry-go-round for a time Δt= 12s . For your calculations, assume the children to be point masses.
----------------------------------
A playground merry-go-round has a radius of R= 4 m and has a moment of inertia Icm= 9×103kg⋅m2 about a vertical axis passing through the center of mass. There is negligible friction about this axis. Two children each of mass m= 25kg are standing on opposite sides at a distance ro= 3.2m from the central axis. The merry-go-round is initially at rest. A person on the ground applies a constant tangential force of F= 2.0×102N at the rim of the merry-go-round for a time Δt= 12s . For your calculations, assume the children to be point masses.
Answered by
Shashanoid
please tell the value for KE :(
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.