Question
A 5.2-m-diameter merry-go-round is initially turning with a 3.0s period. It slows down and stops in 28s.
i found the v = 5.4 m/s, How many revolutions does the merry-go-round make as it stops?
i found the v = 5.4 m/s, How many revolutions does the merry-go-round make as it stops?
Answers
drwls
Average rev/min = (1/2)*(20 rev/min)
= 10 rev/min
No. of revolutions = 10 rev/min*(28/60 min = 4.66
You do not need to know the diameter.
= 10 rev/min
No. of revolutions = 10 rev/min*(28/60 min = 4.66
You do not need to know the diameter.