Question
logarithms
Solve the following equations
3^x-2=6
Add 2 to both sides of the equation to start. Whatever operation you do to one side of an equation you must do to the other side as well.
3^x - 2 + 2 = 6 + 2
3^x = 8
Changing to logs:
log 3^x = log 8
x log 3 = log 8
x = log 8 / log 3
x = 1.8928 -->this is a rounded value.
This should check with the original equation.
I hope this helps.
Solve the following equations
3^x-2=6
Add 2 to both sides of the equation to start. Whatever operation you do to one side of an equation you must do to the other side as well.
3^x - 2 + 2 = 6 + 2
3^x = 8
Changing to logs:
log 3^x = log 8
x log 3 = log 8
x = log 8 / log 3
x = 1.8928 -->this is a rounded value.
This should check with the original equation.
I hope this helps.