how to solve logarithms symbolically?

log17(17)^(x+3)= log7(1)

thank you

1 answer

(x+3) log17(17) = log7(1)

a^(loga b) = b
17^log17(17) = 17 so log17(17)=1
7^log7(1) = 1 so log7(1) = 0 (because7^0=1)
so we have
(x+3)(1)=0
x = -3
Similar Questions
  1. If log710≈1.183log 7 ⁡ 10 ≈ 1.183 and log720≈1.540 log 7 ⁡ 20 ≈ 1.540 , what is log7(10⋅20) log 7 ⁡ ( 10 ⋅ 20
    1. answers icon 1 answer
  2. Solve:2^(5x-6) = 7 My work: log^(5x-6) = log7 5x - 6(log2) = log7 5x = log7 + 6(log2) x = (log7 + log2^6) / 5 And textbook
    1. answers icon 2 answers
    1. answers icon 1 answer
  3. Can someone see if I got these correct?1. Solve log5 x = 3. x = 125 2. log3 (x - 4) > 2. x > 13 3. Evaluate log7 49. log7 49 = 2
    1. answers icon 2 answers
more similar questions