Asked by mike

Use logarithms to solve log 8 / log x < 1.

I understand that there are 2 cases: when x is negative or positive.

I don't understand how it affects the answer though.

Answers

Answered by bobpursley
log8<logx if logx is positive
10^8<x

Log8>logx if logx is negative.
10^8>x if x is less one
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions