Asked by mike
Use logarithms to solve log 8 / log x < 1.
I understand that there are 2 cases: when x is negative or positive.
I don't understand how it affects the answer though.
I understand that there are 2 cases: when x is negative or positive.
I don't understand how it affects the answer though.
Answers
Answered by
bobpursley
log8<logx if logx is positive
10^8<x
Log8>logx if logx is negative.
10^8>x if x is less one
10^8<x
Log8>logx if logx is negative.
10^8>x if x is less one
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