Asked by Anonymous

logarithms

solve for x

5^(x-1) = 9
Answered by bobpursley
take the log base 5 of each side

x-1=log5 9=log10 9 /( log10 5)

http://www.sosmath.com/algebra/logs/log4/log43/log43.html
Answered by Anonymous
?

can i do
x-1= log9/log6
x=(log9/log5) + 1 ?
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