Asked by Me
David is driving at a steady 36.0 m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady 1.20 m/s2 at the instant when David passes. How far (in m) does Tina drive before passing David?
Answers
Answered by
Damon
d = 36 t
d = (1/2)(1.2) t^2
so
36 t = 0.6 t^2
t = 36/.6
then d = 36 t so d = (36)^2/.6
d = (1/2)(1.2) t^2
so
36 t = 0.6 t^2
t = 36/.6
then d = 36 t so d = (36)^2/.6
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