Asked by bobby
A car is traveling at a steady 81 km/h in a 50 km/h zone. A police motorcycle takes off at the instant the car passes it, accelerating at a steady 8.2 m/s2 .
How far is the motorcycle from the car when it reaches this speed?
How far is the motorcycle from the car when it reaches this speed?
Answers
Answered by
Anonymous
car:
81 km /hr * (1 hr/3600 s) * (1000 m/km) = 22.5 m/s
travels for time T
so xcar= 22.5 T
motorcycle
v = 8.2 t= 22.5
t = 22.5/8.2 = 2.74 seconds accelerating = T car
x cycle = (1/2) a t^2 = (1/2)(8.2)(2.74)^2 = 30.9 meters
and
xcar = 22.5 * 2.74 = 61.7 meters
61.7 - 30.9 = 30.8 meters behind
81 km /hr * (1 hr/3600 s) * (1000 m/km) = 22.5 m/s
travels for time T
so xcar= 22.5 T
motorcycle
v = 8.2 t= 22.5
t = 22.5/8.2 = 2.74 seconds accelerating = T car
x cycle = (1/2) a t^2 = (1/2)(8.2)(2.74)^2 = 30.9 meters
and
xcar = 22.5 * 2.74 = 61.7 meters
61.7 - 30.9 = 30.8 meters behind
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