Asked by Paula
David, who is 65 kg, is driving his car at a speed of 25 m/s. He sees a dog crossing the road and so he steps on the brake to avoid hitting it. His seatbelt brings his body to a stop in 0.4 s. What magnitude of force does the seatbelt exert on him?
Answers
Answered by
Steve
The velocity changes by -25 m/s in 0.4 s, so the acceleration is
25/.4 m/s^2 = 62.5 m/s^2
Since F=ma, the force exerted is
65 kg * 62.5 m/s^2 = 4062.5 N
25/.4 m/s^2 = 62.5 m/s^2
Since F=ma, the force exerted is
65 kg * 62.5 m/s^2 = 4062.5 N
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.