Asked by Luc
A box of mass 5 kg is pulled along a horizontal frictionless surface by a force of 40N inclined @ 30dgrees. Calculate A)the work done by the force over a distance. B)the speed gained by the box after travelling 10m.
Answers
Answered by
drwls
The force component in the direction of motion is 40 cos30 N = 34.64 N
A) 34.64 N * distance
(You left out the distance)
B) Set the work done over 10 m equal to final kinetic energy and solve for V.
A) 34.64 N * distance
(You left out the distance)
B) Set the work done over 10 m equal to final kinetic energy and solve for V.
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