Asked by Anny
A 20kg mass is to be pulled up a slope inclined at 30 degree to the horizontal.If the efficiency of the plane is 75% find the force required to pull the load up the plane.
Answers
Answered by
Henry
Wm = 20 kg * 9.8 N./kg = 196 N. = Weight of mass.
Fm = 196 N. @ 30 Deg. = Force of mass.
Fp = 196*sin30 = 98 N. = Force parallel
to plane.
Fv = 196*cos30 = 169.7 N. = Force perpendicular to plane.
Fn = 0.75Fap - Fp = 0,
0.75Fap - 98 = 0,
0.75Fap = 98,
Fap = 130.7 N. = Force applied.
Fm = 196 N. @ 30 Deg. = Force of mass.
Fp = 196*sin30 = 98 N. = Force parallel
to plane.
Fv = 196*cos30 = 169.7 N. = Force perpendicular to plane.
Fn = 0.75Fap - Fp = 0,
0.75Fap - 98 = 0,
0.75Fap = 98,
Fap = 130.7 N. = Force applied.
Answered by
Henry
M*g = 20 * 9.8 = 196 N.
Fap = 196*sin30/0.75 = 130.7 N. = Force applied.
Fap = 196*sin30/0.75 = 130.7 N. = Force applied.
Answered by
Anonymous
A 20KG MASS IS TO BE PULLED UP A SLOPE INCLINED AT 30 TO THE HORIZONTAL IF THE EFFICIENCY OF THE PLANE IS 75% FIND THE FORCE REQUIRED TO PULL THE LOAD UP THE PLANE
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