Asked by Furkan
A mass, 5.0 kg is being pulled from rest with an applied force of 25N. The friction force is 10.0N. How far has it moved after 6.0s?
Answers
Answered by
Henry
a = (Fap-Fk)/M = (25-10)/5 3 m/s^2.
d = 0.5a*t^2.
d = 0.5a*t^2.
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