Asked by Steff
Find the indefinite integral.
∫((e^-x-1)/(e^-x + x)^2) dx
I am trying to use the substitution method.
u=e^-x + x
du= -e^-x+1 dx
Right so far?
∫((e^-x-1)/(e^-x + x)^2) dx
I am trying to use the substitution method.
u=e^-x + x
du= -e^-x+1 dx
Right so far?
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