Find the indefinite integral.
∫((e^-x-1)/(e^-x + x)^2) dx
I am trying to use the substitution method.
u=e^-x + x
du= -e^-x+1 dx
Right so far?
2 answers
got it figured out.
Go to:
wolframalpha dot com
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integrate ((e^-x-1)/(e^-x + x)^2) dx
and click option =
When you see solution click option:
Indefinite integral:Show steps
wolframalpha dot com
When page be open in rectangle type:
integrate ((e^-x-1)/(e^-x + x)^2) dx
and click option =
When you see solution click option:
Indefinite integral:Show steps
1 answer