Question
Find the indefinite integral of (1-sqrtx)/(1+sqrtx)dx
I just worked completely through this problem using substitution (u=1+sqrtx) and came to the answer 3+4sqrtx+x+C.
This is incorrect. Not sure where I messed up.
I just worked completely through this problem using substitution (u=1+sqrtx) and came to the answer 3+4sqrtx+x+C.
This is incorrect. Not sure where I messed up.
Answers
well, first multiply top and bottom by
(1 - sqrt x)
(1-sqrt x)^2
------------ dx
1 - x
(1- 2 sqrt x )^2
------------ dx
1 - x
dx/(1-x) - 2 x^.5 dx/(1-x) + 4 x dx/(1-x)
(1 - sqrt x)
(1-sqrt x)^2
------------ dx
1 - x
(1- 2 sqrt x )^2
------------ dx
1 - x
dx/(1-x) - 2 x^.5 dx/(1-x) + 4 x dx/(1-x)
now go to
http://www.wolframalpha.com/input/?i=integrate+x%2F%281-x%29
http://www.wolframalpha.com/input/?i=integrate+x%2F%281-x%29
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